Q. Write a Odd and Even number pattern in C language as following:
1
2 4 6
1 3 5 7 9
2 4 6 8 10 12 14
1 3 5 7 9 11 13 15 17
Ans.
/* even odd number pattern program in c*/
#include<stdio.h>
int main()
{
int r,c,n,p;
for(r=1,n=1; r<=5; r++,n=n+2)
{
if(r%2==0)
{
for(c=1,p=2; c<=n; c++,p=p+2)
printf(" %d", p);
}
else
{
for(c=1,p=1; c<=n; c++,p=p+2)
printf(" %d", p);
}
printf("\n");
}
getch();
return 0;
}
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1
2 4 6
1 3 5 7 9
2 4 6 8 10 12 14
1 3 5 7 9 11 13 15 17
Ans.
/* even odd number pattern program in c*/
#include<stdio.h>
int main()
{
int r,c,n,p;
for(r=1,n=1; r<=5; r++,n=n+2)
{
if(r%2==0)
{
for(c=1,p=2; c<=n; c++,p=p+2)
printf(" %d", p);
}
else
{
for(c=1,p=1; c<=n; c++,p=p+2)
printf(" %d", p);
}
printf("\n");
}
getch();
return 0;
}
/*******************************************************
The output of above program would be:
******************************************************/
Figure: Screen shot of Output of Odd and Even Number Pattern Program In C |
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