## 2.05.2016

### Character Pattern of Half Diamond

Q. Write a C program to print the following design of Character Pattern of Half Diamond as:

D

CDC
BCDCB
ABCDCBA
BCDCB
CBC
D

Ans.

/*c program for character pattern of half diamond*/
#include<stdio.h>
int main()
{
char ch,r,c,p,q,z;
printf("Enter seed character : ");
scanf("%c", &ch);
if(ch>='a' && ch<='z')
ch=ch-32;
printf("\n\n");
for(r='A',z=ch; r<=ch; r++,z--)
{
for(c=r,p=z; c>='A'; c--,p++)
printf("%c",p);
for(c=r,p=ch-1; c>'A'; c--,p--)
printf("%c",p);
printf("\n");
}
for(r='A',z=ch-1; r<ch; r++,z--)
{
for(c=r,p=r+1; c<ch; c++,p++)
printf("%c",p);
for(c=z,p=ch-1; c>'A'; c--,p--)
printf("%c",p);
printf("\n");
}
getch();
return 0;
}

/****************************************************************

The output of above character pattern of half diamond would be:
***************************************************************/
 Figure: Screen shot for Character Pattern of Half Diamond C Program

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4
343
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1234321
23432
343
4

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1. *
*A*
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can you post soluion for this ?

1. #include
#include
int main()
{
int i,j,m;
for(i=1;i<=5;i++)
{
printf("*");
m=65;
for(j=1;j<i;j++)
{
printf("%c*",m++);
}
printf("\n");
}
return 0;
}

2. #include
#include
int main()
{
int i,j,m;
for(i=1;i<=5;i++)
{
m=65;
for(j=1;j<=i*2-1;j++)
{
if(j%2==0)
printf("%c",m++);
else
printf("*");
}
printf("\n");
}
return 0;
}