Q. Write a C program to print the following triangle:
| * | ||||||||||
| * | * | * | ||||||||
| * | * | * | * | * | ||||||
| * | * | * | * | * | * | * | ||||
| * | * | * | * | * | * | * | * | * | ||
| * | * | * | * | * | * | * | * | * | * | * |
Ans.
/*c program for star pyramid*/
#include<stdio.h>
#include<conio.h>
int main()
{
int num=6,r,c,sp;
for(r=1; num>=r; r++)
{
for(sp=num-r; sp>=1; sp--)
printf(" ");
for(c=r; c>=1; c--)
printf("*");
for(c=r; c>1; c--)
printf("*");
printf("\n");
}
getch();
#include<stdio.h>
#include<conio.h>
int main()
{
int num=6,r,c,sp;
for(r=1; num>=r; r++)
for(sp=num-r; sp>=1; sp--)
printf(" ");
for(c=r; c>=1; c--)
printf("*");
for(c=r; c>1; c--)
printf("*");
printf("\n");
}
| * | ||||||||||
| * | * | * | ||||||||
| * | * | * | * | * | ||||||
| * | * | * | * | * | * | * | ||||
| * | * | * | * | * | * | * | * | * | ||
| * | * | * | * | * | * | * | * | * | * | * |
Very helpful best site visited so far:-))
ReplyDeletei need a c code to print the following triangle
ReplyDelete5
5 5
5 5 5
5 5 5 5
@Femi,
DeleteYour required source code of above program as:
#include "stdio.h"
int main()
{
int num=5,r,c;
for(r=1; r<num; r++)
{
for(c=1; c<=r; c++)
printf("%d",num);
printf("\n");
}
getch();
return 0;
}
I need a code for the following patter (Using recursive function).
ReplyDeleteHelp is appreciated.
*
* *
* * *
* * * *
#include
Delete#include
main()
{
int i,j,n;
printf("Enter the number of rows:- ");
scanf("%d", &n);
for(i=1;i<=n;i++)
{
for(j=1;j<=i;j++)
{
printf("*");
}
printf("\n");
}
getch();
}
it was simple
Deleteif i put +i,++j instead of i++, j++ in this program.was the program works with same output.?
DeleteI need a code to print the following pyramid:
ReplyDelete1
22
333
4444
55555
666666
Console.Write("enter how many rows you want:");
Deleteint number=int.Parse(Console.ReadLine());
for(row=1;row<=number;row++)
{
for(col=1;col<=row;col++)
{
Console.Write(row);
}
Console.WriteLine();
}
/*
ReplyDelete1
22
333
4444
55555
for (int i=1;i<=5; i++) {
for (int j=1; j<=i; j++) {
NSLog(@"%i",i);
}
NSLog(@"\n");
}
*/
Sir,
ReplyDeleteI need a code.example input height 3,base 2,oreentation:
orientation1: **
****
******
orientation2: ********
****
**
orientation3:
**
****
********
orientation4:
********
****
**
orientation5:
**
****
********
orientation 6:
********
****
**
hello
ReplyDeletei need a code to convert number to words
#include
Delete#include < conio.h >
void main()
{
long num,div,n1;
int flag,digit,pos,tot_dig;
clrscr();
printf("\n Enter number: ");
scanf("%ld",& num);
if(num==0)
{
printf("Zero\n\n");
exit(0);
}
if(num>99999)
{
printf("please enter number between 0 and 100000\n\n");
exit(0);
}
tot_dig = 0;
div = 1;
n1 = num;
while ( n1 > 9 )
{
n1 = n1 / 10;
div = div * 10;
tot_dig++;
}
tot_dig++;
pos = tot_dig;
while ( num != 0 )
{
digit= num / div;
num = num % div;
div = div / 10;
switch(pos)
{
case 2:
case 5: if ( digit == 1 )
flag = 1;
else
{
flag = 0;
switch(digit)
{
case 2: printf("twenty ");break;
case 3: printf("thirty ");break;
case 4: printf("forty ");break;
case 5: printf("fifty ");break;
case 6: printf("sixty ");break;
case 7: printf("seventy ");break;
case 8: printf("eighty ");break;
case 9: printf("ninty ");
}
}
break;
case 1:
case 4: if ( flag == 1 )
{
flag = 0;
switch(digit)
{
case 0 : printf("ten ");break;
case 1 : printf("eleven ");break;
case 2 : printf("twelve ");break;
case 3 : printf("thirteen ");break;
case 4 : printf("fourteen ");break;
case 5 : printf("fifteen ");break;
case 6 : printf("sixteen ");break;
case 7 : printf("seventeen ");break;
case 8 : printf("eighteen ");break;
case 9 : printf("ninteen ");
}
}
else
{
switch(digit)
{
case 1 : printf("one ");break;
case 2 : printf("two ");break;
case 3 : printf("three ");break;
case 4 : printf("four ");break;
case 5 : printf("five ");break;
case 6 : printf("six ");break;
case 7 : printf("seven ");break;
case 8 : printf("eight ");break;
case 9 : printf("nine ");
}
}
if ( pos == 4 )
printf("thousand ");
break;
case 3:
if ( digit> 0 )
{
switch(digit)
{
case 1 : printf("one ");break;
case 2 : printf("two ");break;
case 3 : printf("three ");break;
case 4 : printf("four ");break;
case 5 : printf("five ");break;
case 6 : printf("six ");break;
case 7 : printf("seven ");break;
case 8 : printf("eight ");break;
case 9 : printf("nine ");
}
printf("hundred ");
}
break;
}
pos--;
}
if ( pos == 4 && flag == 0)
printf("thousand");
else
if ( pos == 4 && flag == 1)
printf("ten thousand");
if ( pos == 1 && flag == 1 )
printf("ten ");
getch();
}
here is a short code to convert 3 digit number to word :
Delete#include
#include
#include
#include
int main()
{
int i;
int j[4];
printf("\t\t enter a three digit number\n");
scanf("%d",&i);
printf("number u have entered is %d\n",i);
if(i>=1000)
{
printf(" enter valid 3 digit number");
}
else
{
j[3]=i%100;
j[2]=i%10;
j[1]=(i/10)%10;
j[0]=(i/100);
char c[9][9]={"one","two","three","four","five","six","seven","eight","nine"};
char d[10][10]={"ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eigthteen","nineteen"};
char e[10][10]={"twenty","thirty","forty","fifty","sixty","seventy","eighty","ninety"};
if(j[0]!=0)
{
printf("%s hundred ",c[j[0]-1]);
}
if(j[1]==0 && j[2]!=0)
{
printf("and %s",c[j[2]-1]);
}
if(j[3]<20 && j[3]>9)
{
printf("and %s",d[j[3]-10]);
}
else if(j[1]!=0)
{
printf("and %s ",e[j[1]-2]);
if(j[2]!=0)
{
printf("%s",c[j[2]-1]);
}
}
}
getch();
return 0;
}
if i put ++r,--sp,--c instead of r++, sp-- ,c--in this program.was the program works with same output.?
ReplyDelete#include
ReplyDeletevoid main()
{
int x,i;
for(x=1;x<=5;x++)
{
for(i=1;i<=x;i++)
{
printf("*");
}
printf("\n");
}
}
entify the logic behind the series
ReplyDelete6 28 66 120 190 276....
The numbers in the series should be used to create a Pyramid. The base of the Pyramid will be the widest and will start converging towards the top where there will only be one element. Each successive layer will have one number less than that on the layer below it. The width of the Pyramid is specified by an input parameter N. In other words there will be N numbers on the bottom layer of the pyramid.
The Pyramid construction rules are as follows
First number in the series should be at the top of the Pyramid
Last N number of the series should be on the bottom-most layer of the Pyramid, with Nth number being the right-most number of this layer.
Numbers less than 5-digits must be padded with zeroes to maintain the sanctity of a Pyramid when printed. Have a look at the examples below to get a pictorial understanding of what this rule actually means.
Example
If input is 2, output will be
00006
00028 00066
If input is 3, output will be
00006
00028 00066
00120 00190 00276
Formal input and output specifications are stated below
Input Format:
Firs
hello,I know the popularity of you thats why i am commenting
ReplyDeleteCan you please help me in making these 2 programs as i am new to programming:
I would be highly thankful to you
Program 1
Write a program which takes an integer input from the user (max value can be 8). The program then creates a matrix which displays the power of the input integer which is incremented in each column and subsequent row. For example, if a user enters the value 5, then the output should look like:
1 1 1 1 1
2 4 8 16 32
3 9 27 81 243
4 16 64 256 1024
5 25 125 625 3125
program 2:
Write a program which moves the character ‘X’ in a 5x5 Matrix at the output. The input to this program is a character from the user: ‘w’, ‘a’, ‘s’ and ‘d’, in order to move ‘X’ up, left, down, and right. If user enters ‘0’, then the program should exit. Make sure that the character ‘X’ is not able to move outside the limits.
The sample run of the program at the start is:
. . . . .
. . . . .
. . X . .
. . . . .
. . . . .
Enter the direction:
If user enters ‘w’, then ‘X’ should move up:
. . . . .
. . X . .
. . . . .
. . . . .
. . . . .
Enter the direction:
If user enters ‘a’, then ‘X’ should move left:
. . . . .
. X . . .
. . . . .
. . . . .
. . . . .
Enter the direction:
And so on…
Make Sure that ‘X’ does not go outside the 5x5 limit
Waiting for your reply ,
thank you.
@Salman
Deleteyour Program 1 number triangle C source code as:
#include "stdio.h"
int main()
{
int num=5,r,c,p;
for(r=1; r<=num; r++)
{
for(c=1,p=r; c<=num; c++)
{
printf(" %d ", p);
p=p*r;
}
printf("\n");
}
return 0;
}
thanks plz tell me solution of 2nd program
DeleteBro kindly upload the solution of 2nd program.
Deletenot yet got my program kindly tell me if cannot solve it
Delete